p^2-p-110=0

Solution for p^2-p-110=0 equation:

p^2-p-110=0

We add all the numbers together, and all the variables

p^2-1p-110=0

a = 1; b = -1; c = -110;
Δ = b2-4ac
Δ = -12-4·1·(-110)
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{441}=21$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-21}{2*1}=\frac{-20}{2}
=-10
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+21}{2*1}=\frac{22}{2}
=11
$